Alternating Current: CBSE 2026 weightage, key formulas, JEE trends and prep hours

Alternating Current in CBSE 2026 carried higher weight (12–15 marks). This brief lists official Unit IV marks, JEE Main/Advanced trends, must-know formulas, resonance facts and suggested revision hours for Class 12 students.

Edited by Rajeev Menon

Updated April 18, 2026 4:02 AM

    Alternating Current

    Article updated: Apr 16, 2026.

    Alternating Current appears as a high-yield topic for Class 12 Physics and competitive exams. The official NCERT/CBSE syllabus places Unit IV (Electromagnetic Induction and Alternating Currents) at 8 marks , but analysis of CBSE 2026 papers shows AC-related questions totaling 12–15 marks (about 18–22% of the unit in that year).

    Alternating Current: CBSE and JEE weightage

    Here are the standard weight trends from official papers and recent 2026 analysis.

    Exam / Source Typical weight / questions
    CBSE (official Unit IV) 8 marks (unit total)
    CBSE 2026 papers (actual) 12–15 marks (6–8 questions)
    JEE Main 6–8 marks (2–3 questions)
    JEE Advanced 8–12 marks (2–3 questions)

    Around 50–60% of 2026 AC questions focused on series LCR and resonance; the paper mix was roughly 60% numerical and 40% conceptual .

    Alternating Current: Key formulas and facts

    Memorise these for quick reference. They appear frequently in board and JEE questions.

    Quantity Formula / Value
    RMS current/voltage I_rms = I0/√2 ; V_rms = V0/√2 (≈ 0.707×peak)
    Average current (half-cycle) I_avg = 2I0/π ≈ 0.637 I0
    Inductive reactance X_L = ωL
    Capacitive reactance X_C = 1/(ωC)
    Impedance (series LCR) Z = √(R^2 + (X_L − X_C)^2)
    Phase angle tan φ = (X_L − X_C)/R
    Resonant frequency f_r = 1/(2π√(LC))
    Average power P_avg = V_rms I_rms cos φ
    Transformer turns ratio E_s/E_p = N_s/N_p

    At resonance X_L = X_C, Z = R and φ = 0 (power factor = 1). These are frequent test points.

    How much time to revise

    Recommended revision from official exam trends: spend 4–6 hours to revise theory, diagrams and basic numericals for CBSE Boards. For JEE-focused numerical practice, allow 8–12 hours on series LCR, resonance and transformer problems.

    Coverage notes from official papers

    CBSE 2026 included more numerical and case-based questions on resonance and LCR than usual. JEE papers continue to test multi-step numericals, phasor reasoning and power-factor questions.

    FAQs

    How many marks is Alternating Current in CBSE Class 12?
    A: Official Unit IV is 8 marks , but CBSE 2026 question papers had 12–15 marks from AC topics.
    What is the RMS value?
    A: I_rms = I0/√2 and V_rms = V0/√2 (≈ 0.707 of peak).
    What is the resonance condition?
    A: Resonance when ω_r = 1/√(LC); X_L = X_C; Z = R; φ = 0.
    Which AC topics are highest-yield?
    A: Series LCR, resonance, impedance, RMS/average values, transformers, power factor and phasors.
    How to divide study time for AC?
    A: 4–6 hours for CBSE revision; 8–12 hours for JEE numericals and practice.
    What is impedance formula?
    A: Z = √(R^2 + (X_L − X_C)^2).
    What is average current over half cycle?
    A: I_avg = 2I0/π ≈ 0.637 I0.
    Where do these numbers come from?
    A: Figures are taken from official NCERT/CBSE syllabus and analysis of CBSE 2026 and JEE trends.

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